### Problem 7
Suppose \( R \) is the relation on \( \mathbb{Z} \times \mathbb{Z} \) where \( aRb \) means that \( a \) has the same lowest order (right-most) digit as \( b \).
**Example:**
\((a, b) \in R\) when \( a = 1234 \) and \( b = 64 \) because both numbers end in 4.
Determine whether \( R \) is an equivalence relation. Show your reasoning.
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### Solution
Yes, \( R \) is an equivalence relation.
- **Reflexive:**
\( a \) ends with the same digit as itself, so \((a, a) \in R\).
- **Symmetric:**
If \( a \) ends with the same digit as \( b \), then \( b \) ends with the same digit as \( a \).
Thus, if \((a, b) \in R\), then \((b, a) \in R\).
- **Transitive:**
If \( a \) ends with the same digit as \( b \), and \( b \) ends with the same digit as \( c \), then \( a \) ends with the same digit as \( c \).
Hence, \((a, c) \in R\).
If asked this on the final, you must show proof of all three required properties.